- Identity P ^ T <==> P % Rules w/ one proposition
- Identity P v F <==> P
- Domination P ^ F <==> F
- Domination P v T <==> T
- Negation P ^ ~P <==> F
- Negation P v ~P <==> T
- Idempotent P ^ P <==> P
- Idempotent P v P <==> P
- Commutative Law P ^ Q <==> Q ^ P % Rules w/ two propositions
- Commutative Law P v Q <==> Q v P
- DeMorgans Law ~(P v Q) <==> (~P ^ ~Q)
- DeMorgans Law ~(P ^ Q) <==> (~P v ~Q)
- Implies Rule P --> Q <==> (~P v Q)
- Contrapositive: P --> Q <==> ~Q --> ~P
- Absorption P ^ (P v Q) <==> P
- Absorption P v (P ^ Q) <==> P
- Associative Law P v (Q v R) <==> (P v Q) v R % Rules w/ 3 propositions
- Associative Law P ^ (Q ^ R) <==> (P ^ Q) ^ R
- Distributive Law P ^ (Q v R) <==> (P ^ Q) v (P ^ R)
- Distributive Law P v (Q ^ R) <==> (P v Q) ^ (P v R)
in a tautology, every possible possible way of assigning truth values to the propositions leads to an expression which is true.Q --> (~P v Q) <==> T
in a contradiction, every possible possible way of assigning truth values to the propositions leads to an expression which is false.
What do we have to do to prove that we don't need a specific connective?
Why do we use the set of connectives that we do?
Today we start with a few more examples of propositional equivalence. First, for practice, we prove one rule of equivalance as true.
Contrapositive: Prove this is logically equivalent...
a --> b <==> ~b --> ~a ~a v b <==> ~b --> ~a "implies rule" ~a v b <==> ~~b v ~a "implies rule" ~a v b <==> b v ~a "double negation" ~a v b <==> ~a v b "commutative rule"
Second, Can we add to the list of nice rules about "--->"? Prove or disprove the "associative rule of implication".
(p --> q) --> r <==> p --> (q --> r)
~(~p v q) v r ( we're just seeing if it works... so don't have to
do all the steps )
(p ^ ~q) v r <==> ~p v (~q v r)
this looks alllll different. So find some way of assigning T,F to
all the variables so that the two sides have different truth values.